calculus
posted by quita .
Differentiate
y=lnx
You ought to have this memorized.
y'=1/x
for y= ln x
dy/dx = 1/x
This is the most basic and fundamental of log derivatives.
If you are studying Calculus, and the topic is logs, I fail to understand why you asked that question.
IS there a website that can better explain logs?
Hmmm. This is an odder question, for a person taking calculus. I suspect you need to ask yourself the question if you are in over your head.
I can recommend Schaum's Outline Series: College Calculus, a very good problem oriented book. It is about 17 dollars at your college bookstore, or BarnesNoble, or Amazon. It is well worth it.
Now your question "better explain logs".The problem did not deal with logs, it dealt with a basic differential of a log function. That should be memorized, just as d(sinx)/dx is memorized as cosx.
If you want help in log functions. try
http://www.physics.uoguelph.ca/tutorials/LOG/
This a basic tutorial for precal students.
http://www.themathpage.com/aPreCalc/logarithms.htm
Thanks for the info..And yes I may be in over my head, but with my grades you wouldnt know it...So far so good...
Respond to this Question
Similar Questions

CALCULUS
what is the derivative of ln(x1)? If you are studying the calculus of logarithms your question surprises me, since that is one of the most basic ones in that topic. in general if y = ln("anything") then y' = 1/"anything" * derivative 
calculus
find the following derivatives: f(x) = (2x+5)/(x^23) f'(x)= (2)*(x^2 3)(2x+5)*2x/(x^23)^2 is that correct? 
Math
Find the coordinates of the turning point and determine wether it is minimum or maximum. y=xlnx2x The answer in the book says the coordinates are (e,e), the closest I have come is (1/lnx,1/lnx) which works if 1/lnx=e, but I don't … 
Calculus AB (AP)
Hi, I have a calculus test tomorrow and I understand how to complete all of the problems, but I am unsure behind the reasoning of taking two derivatives. Can someone please explain the following: 1. g(x)=e^(f(x)) g'(x)=e^(f(x))f'(x) … 
Calculus 1
Find the derivative of y with respect to x. y=(x^6/6)(lnx)(x^6/36) So far this is what I've gotten: y=(x^6/6)(lnx)(x^6/36) y=(1/6)x^6(lnx)(1/36)x^6 y'=(1/6)x^5(1/x)+lnx(x^5)(1/6)x^5 What do I do now? 
calculus
sorry to ask a second question so soon, but i'm just not getting this one. if f(x)= 3x lnx, then f'(x)=? 
Calculus
Find the derivatives, dy/dx for the following functions. a. x^2y^4 = lnx + 3y b. y = ln(2x^2 + 1) c. y = ln(ãx) d. y = lnx/x e. y = x^2 lnx f. y ß log_2(3x) 
Calculus
Differentiate y=log(8x^23x+9) 
Calculus
what is the limit as h approaches 0 of ((x+h)^pix^pi)/h? 
Calculus
Find the minimum distance between the curves y=e^x and y=lnx. Hint: Use the fact that e^x and lnx are inverse relationships. I have no idea where to start. Thanks! calculus  Reiny, Monday, January 18, 2016 at 9:02pm to get you going: …