# physics

posted by
**Cavin**
.

A pendulum clock can be approximated as a simple pendulum of length 1.20m and keeps accurate time at a location where G=9.83m/s2. In a location where g=9.73m/s2, what must be the new length of the pendulum, such that the clock continues to keep accurate time9 that is, its period remains the same)?

Isnt Period on a pendulum clock equal to

2PI sqrt (length/g) ?

so if the period are the same, setting them equal

2PI sqrt (1.2/8.83) = 2PI sqrt (length/9.73)

solve for length.