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A spring (k = 857 N/m) is hanging from the ceiling of an elevator, and a 5.9 kg object is attached to the lower end. By how much does the spring stretch (relative to its unstrained length) when the elevator is accelerating upward at a = 0.81 m/s2?

force= kx
solve for a.

  • Physics -

    Use kx=mg+ma
    857x = (5.9*9.8) + (5.9*.81)
    thus, x= .073

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