Four 20 ohm resistors are connected in parallel and the combination is connected to a 20 V emf device. The current in any one of the resistors is:
A) 0.25 A
B) 1.0 A
C) 4.0 A
D) 5.0 A
E) 100 A
I get B V=IR
I= 20V/20 ohms = 1 A for any one of the resistors
thank you
correct.
You are correct! To find the current in any one of the resistors, you can use Ohm's Law, which states that V = IR, where V is the voltage across the resistor, I is the current through the resistor, and R is the resistance of the resistor.
In this case, the voltage across each resistor is 20 V (given by the emf device), and the resistance of each resistor is 20 ohms. Therefore, the current through each resistor is:
I = V / R = 20 V / 20 ohms = 1 A.
Hence, the correct answer is option B) 1.0 A. Well done!
The current in any one of the resistors is indeed 1.0 A. This is because when resistors are connected in parallel, the total resistance is given by the reciprocal of the sum of the reciprocals of each individual resistance. In this case, since all resistors have the same value of 20 ohms, the reciprocal of the total resistance is 1/20 + 1/20 + 1/20 + 1/20 = 1/5. Therefore, the total resistance is 5 ohms.
According to Ohm's law, V = IR, where V is the voltage across the resistor, I is the current flowing through it, and R is the resistance. Given that the voltage across each resistor is 20 V, we can rearrange the equation to solve for I:
I = V/R = 20 V / 20 ohms = 1.0 A.
Thus, the correct answer is B) 1.0 A.