math, correction plz
posted by jas20 .
Can someone correct these for me.PLZ
Problem#1
Directions solve equation
ãx+4 = 3
My answer: x = 5
Probelm #2
Directions solve equation
ã(4x+1) + 3 = 0
My answer x = 2
Problem #3
Directions solve equation
ã(2y+7)+4=y
My answer y= 1 and y = 9
the symbol a is a radical it came out wrong.
the first one is correct
Use brackets to show which parts are below the square root sign
in the second:
√(4x+1)+3=0
√(4x+1)=3
square both sides etc.
You should have been told that if you obtain algebraic answers after "squaring" , all solutions have to be verfied.
If you check your answer of x=2, it does not satisfy the original equation.
So the second equation has no real solution.
The same is true for your third equation.
Even though y=1 and y=9 are algebraic solutions, when you check the answers in the original equation, only y=9 works, the other answer is not valid.
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