# math

posted by .

(n-2)*180 =108n

180 n - 108 n = 360
72 n = 360
n = 5

(n-2)^180 =108n

been working on it for almost an hour, trying Newton's method and all kinds of iteration.
I really have to try to read the questions more carefully, ha ha

You will have to use a graphical or iterative method (like Newton's) to solve that. There is no explicit closed-form answer.

(n-2)^180 =108n
If n = 3.03, you get 204 (left) & 327 (right)
If n = 3.04, you get 1164 (left) and 328 (right)
If n = 3.0326, you get 322 on the left and 327 on the right

## Similar Questions

1. ### ALGEBRA 1

FOUR OF THE ANGLES OF A PENTAGON HAVE THE MEASURE 30,70, 120, AND 165. TO FIND THE MEASURE OF THE FIFTH I ADD THE FOUR MEASURES WHICH IS 385 AND SUBTRACT IT FROM 540 WHICH IS 540-385=135 WOULD THIS BE CORRECT. IS THERE A FOMULA THAT …
2. ### math

The measure of an interior angle of a regular polygon is 135 degrees. Find the number of sides in the polygon. This is what I tried: 180(x-2)=135 [Interior Angle Sum Theorem] x-2=.75 x=2.75 That can't be right though. Help?
3. ### math

how to define arc cosine(cosine x) for -360 deg<x< 360 deg?
4. ### Algebra 2

The formula A = 180(n-2)/n relates to the measure A of an interior angle of a regular polygon to the number of sides n. If an interior angle measures 120 degrees, find the number of sides A)5 B)6 C)8 D)10 I have NO clue on how to do …
5. ### Math

Solve for n á = (n-2) * 180 / n = 180 – 360/n
6. ### Algebra

Solve for n á = (n-2) * 180 / n = 180 – 360/n
7. ### Trig (Last URGENT)

sin2x+cosx=0 , [-180,180) = 2sinxcosx+cosx=0 = cosx(2sinx+1)=0 cosx=0 x1=cos^-1(0) x1=90 x2=360-90 x2=270 270 doesn't fit in [-180,180) what do I do?