math,help
posted by jasort20 .
help
Probblem #6
solve by multiplying through with the common denominator
(11)/(3)x + (1)/(6) = (8)/(3)x + (19)/(6)
Problem #20
the perimeter of a rectangle is to be no greater than 300in. and the length must be 125in. write an inequality representing the maximum perimeter.
i know that the perimeter is length times width...
#6. First, find the common denominator.
(22/6)X + 1/6 = (16/6)X + 19/6
(22/6)X  (16/6)X = 19/6  1/6
You should be able to take it from here.
#20. Area — NOT perimeter — is length times width. Perimeter is obtained by adding the length of all the sides.
300 > 2(125) + 2X, where X = width
I hope this helps. Thanks for asking.
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