# Math

posted by
**Freddy**
.

Find the derivative of:

ln(2x/x+1)

the answer is 1/x(x+1) but i can't seem to solve it that far.

ln [2x/(x+1)] = ln 2 + ln (x) - ln(x+1)

Add the derivatives of each term and you get

1/x - 1/(x+1) = [(x+1) - x]/[x(x+1)] = 1/[x(x+1)]