Calculus
posted by Steven .
Please.... I need your help! I posted this question yesterday and no one has answered it yet. Can anyone help me please? My question was:
The Taylor series about x=5 for a certain function f converges to f(x) for all x in the interval of convergence. The nth derivative of f at x=5 is given by f^(n) (5)= (1)^n(n!)/((2^n)(n+2)), and f(5)=1/2.
Write third degree Taylor polynomial for f about x=5. Then find the radius of convergence of the Taylor series for f about x=5.
I appreciate your help! Thanks
Do you mean the "nth derivative" or the "nth term in the (first)derivative"? of f(x)? It looks like you have written the coefficient of one term in a Taylor series, without the x^n term coefficient that should accompany it.
x=2
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