# math,correction

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Problem #1

(3x)/(18) minus (x)/(18)

MY steps:
(3x-x)/(18) = (2x)/(18)
(2x)/(18)

Problem #18

write in simplest form.

(3x^5)/(15x^12)

My steps:

(3)/(15) = .60
x^5-12 = x^-7

Problem #21

(x)/(6) + (3x)/(6)

= (x+3x)/(6)

#1 : Yes, but one more step. You can take the 2 and the 18 and figure out how to reduce those. So it would be 1x/9 (Or just x/9)

#2: 3/15 = .2 On a technical level, .2x^-7 would be a correct answer. But not in its simplest form. 1/5 is the same as 3/15, so we can write it like:

1/5x^7

#3 One more step. What can you do with the 4 and 6? (Clue: Look at my reply to question #1 above)

my question is how is the answer

1/5x^7

if the exponent is a negative 7? and you have it as a positive 7

and for problem # 3

would then the last step be:

2x/3

• math -

4 1×4 2×2
10 1×10,2×5 in division

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