calculus
posted by Meredith
The function f has derivatives of all orders for all real numbers x. Assume f(2)=3, f'(2)=5, f''(2)=3, and f'''(2)=8.
The fourth derivative of f satisfies the inequality, the (absolute value of f''''(x)) <=3 for all x in the closed interval [1.5, 2]. Use the Lagrange error bound on the approximation to f(1.5) found in part (a) to explain why f(1.5) does not equal 5.
The part (a) was where I wrote the thirddegree Taylor polynomial for f about x=2 and approximate f(1.5).
I had 3+5(x2) +3(x2)^2/28(x2)^3/6, which was 4.958333 when f(1.5).
Please help me answer this question.
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