factoring
posted by Reiny .
let f(m)=m^3 + 3m^2 + 3m + 1
notice f(1) = 0, so m+1 is a factor.
Using division, the answer is m^2 + 2m + 1 which factors once more to (m+1)(m+1)
so you have (m+1)^3 = 0
and then m = 1
Are you familiar with Pascal's triangle?
Did you notice the pattern in the coefficients 1 3 3 1 and descending powers of m?
good work Reiny.
can anybody help with factoring this problem
m^3 + 3m^2 + 3m + 1 = 0
Does it help to check to see if 1 is a root? If so, x1 can be divided into the polynomial.
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