algebra
posted by kairi .
the other one came out wrong.
8x^2y^2 (4xy^2)^1
________ . ___________
x^2y x^2y
its a fraction and you have to multiply
I assume you mean
[(8x^2 y^2)/(x^2 y)] x [(4xy^2)^1/(x^2 y)]
which can be rewritten
= 8 x^4 y^3 x [1/(4x^3y^3)]
= 2 x y^6
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