precal
posted by raven 31791 .
The sq root of 4 (3sq root of 9)
a)6 +6i
b)6+6i
c)66i
d)66i
Again the i's are in italics. I would think that c and d could be eliminated because the answer is suppose to be in the form a + bi but they could be trting to trick you.
I'm not quite sure what your problem is, so I'm going to assume it's something like the following:
√4(3  √9)
i = √1
i^2 = 1
Note: I'm using ^2 to mean squared.
√4 = 2i
√9 = 3i
Now we have: 2i(3  3i)
Simplifying:
6i  6i^2 =
6i  6(1) =
6i + 6
..or..
6 + 6i
I hope this helps and is what you were asking.
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