hi, how would we find the y intercept , given slope of 11/2.54 and points (5,1.49). can you show me the steps so i can solve it. tnx
y=ax + b where a is slope, b is y intercept. Put the points in the equation...
1.49=11/2.54 (5) + b
solve for b.
x + y = 1 what does the graph look like
To find the y intercept given the slope and a point on the line, you can use the slope-intercept form of a linear equation, which is:
y = mx + b
Where:
m is the slope
b is the y intercept
Step 1: Substitute the given slope into the equation.
The slope given is 11/2.54. So, we have:
y = (11/2.54)x + b
Step 2: Substitute the coordinates of the given point into the equation.
The given point is (5, 1.49). Substitute the values of x and y into the equation:
1.49 = (11/2.54)(5) + b
Step 3: Solve for b.
Now, we can solve the equation for b. Let's simplify the equation and isolate b:
1.49 = (55/2.54) + b
To isolate b, subtract (55/2.54) from both sides of the equation:
1.49 - (55/2.54) = b
Using a calculator to perform the arithmetic, we find that b is approximately equal to -19.6457.
Therefore, the y-intercept is approximately -19.6457.