BobPursley3...another one..
posted by Margie .
Problem 3:
4x/(x+2)  8/(x1)
What I did:
Common denominator is: (x+2)(x1)
4x(x1)/(x+2)(x1)  8(x+2)/(x+2)(x1)
[4x(x1)  8(x+2)]/(x+2)(x1)
multiply the numerator out.
4x^2 4x 8x16
4x^212x16 factor 4 out
4(x^23x4)
factor
4(x4)(x+1)
and that will reduce over the denominator.
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