Geometry. Find the perimeter of the given figure.
tHE Figure is a rectangle.It has height (8)/(2x-5) and length (8)/(2x-5)
My answer is: (2(x+8))/(2x-5)
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Add or subtract as indicated. Express your result in simplest form.
(2)/(5w+10) Subtracted by (3)/(2w-4)
My answer is: (11w+38)/(10(4-w-w^2))
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Add or subtract as indicated. Express your result in simplest form.
(3)/(x^2+4x+3) subtracted by (1)/(x^2-9)
My answer is : (2(x-5))/((x+3)(x-3)(x+1))
First: No. just add the l, h and multiply by two.
second
correct
Third: correct
To find the perimeter of a rectangle, you need to add the lengths of all the sides. In this case, the rectangle has a height of (8)/(2x-5) and a length of (8)/(2x-5).
So, to find the perimeter, you add the length, the height, the length, and the height again, which gives you:
Perimeter = length + height + length + height
Perimeter = (8)/(2x-5) + (8)/(2x-5) + (8)/(2x-5) + (8)/(2x-5)
Since all four sides of a rectangle are equal, you can simplify this to:
Perimeter = 4 * (8)/(2x-5)
Simplifying further, you get:
Perimeter = (32)/(2x-5)
Therefore, the perimeter of the rectangle is (32)/(2x-5).
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To subtract fractions, you need to have a common denominator. In this case, the fractions are (2)/(5w+10) and (3)/(2w-4).
To find a common denominator, you need to multiply the denominators of both fractions together. In this case, the common denominator is (5w+10) * (2w-4).
Now, you can rewrite the fractions with this common denominator:
(2)/(5w+10) = (2 * (2w-4))/((5w+10) * (2w-4))
(3)/(2w-4) = (3 * (5w+10))/((5w+10) * (2w-4))
To subtract these fractions, you need to subtract the numerators while keeping the denominator the same:
Subtraction = (2 * (2w-4))/((5w+10) * (2w-4)) - (3 * (5w+10))/((5w+10) * (2w-4))
With the common denominator, you can combine the numerators:
Subtraction = (4w-8 - 15w-30)/((5w+10) * (2w-4))
Simplifying the numerator, you get:
Subtraction = (-11w-38)/((5w+10) * (2w-4))
Therefore, the subtraction of the fractions is (-11w-38)/((5w+10) * (2w-4)).
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To subtract fractions (3)/(x^2+4x+3) and (1)/(x^2-9), you need to find a common denominator. The denominators in this case are (x^2+4x+3) and (x^2-9).
To find a common denominator, you need to factor the denominators:
(x^2+4x+3) = (x+1)(x+3)
(x^2-9) = (x+3)(x-3)
Now, rewrite the fractions with these factored denominators:
(3)/(x^2+4x+3) = (3)/((x+1)(x+3))
(1)/(x^2-9) = (1)/((x+3)(x-3))
To subtract these fractions, subtract the numerators while keeping the denominator the same:
Subtraction = (3)/((x+1)(x+3)) - (1)/((x+3)(x-3))
With the common denominator, combine the numerators:
Subtraction = (3 - (x+1))/((x+1)(x+3)(x-3))
Simplifying the numerator, you get:
Subtraction = (2-x)/((x+1)(x+3)(x-3))
Therefore, the subtraction of the fractions is (2-x)/((x+1)(x+3)(x-3)).