Algebra
posted by Palace .
How do I solve this?
The perimeter of a rectangular writing pad is 28 inches. The length is 1 inch
less than twice the width. Find the width.
Show all work!
Translate your English into Math
<The length is 1 inch
less than twice the width>
or L = 2W  1
<Perimeter is 28 inches>
2L + 2W = 28
2(2W1) + 2L = 28
I am sure you can solve this
I am just beginning to learn this stuff.
The answer is 7 right?
no
starting from 2(2W1) + 2L = 28
4w  2 + 2L = 28
6W = 28+2
6W=30
W = 5 the L = 2W1
= 101
= 9
check 2(9) + 2(5) = 28
Are you sure? I have 4 choices on my
assignment to mark and 9 isn't on there.
The choices are:
A. 8 inches
B. 7 inches
C. 6 inches
D. 5 inches
Yes I am sure.
My answers were W=5 L=9
notice i had verified my answer.
The original equation should be:
2(2w1)+ 2w = 28 (It used L in the first equation, but L was replaced by 2w1)
Distribute first:
4w2 + 2w = 28
Combine like terms:
6w  2 = 28
Solve:
6w = 30
w = 5
The correct answer is D. Double check it in the original equation.
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