Physics
posted by Jean .
Calculate the force required to pull a copper ball of radius 2.00 cm upward through a fluid at the constant speed 9.00 cm/s. Take the drag force to be proportional to the speed, with proportionality constant 0.950 kg/s. Ignore the buoyant force.
Forcedrag=k v
= .950kg/s * .09m/s= ? joules
I got this answer too.
but the book says the answer is 3.01 N up?
Total force required = Weight + drag = (4/3) pi R^3 * density * g
+ (0.950) kg/s * 9*10^2 m/s
Use g = 9.8 m/s^2,
R = 2*10^2 m,
and density = 8.92*10^3 kg/m^3
AHHH!
thank you SO much.
can i ask you how you got the
"weight" part of the equation?
Weight = Mass * g = Volume*density* g
The answer will be in Newtons, by the way

fdv