# Pre Cal

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(1/3)LN27 + 2LNx = LN(2-x)

i think i just need help getting started.

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(1/3)LN27 + 2LNx = LN(2-x) i think i just need help getting started. I assume that your LN notation is log to base e. I will call it ln. (1/3)ln 27 = ln (27)^(1/3) = ln 3, (since 27^(1/3) is the cube root of 27). Therefore ln 3 + 2 …
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