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I need help solving this:
6x^2-x-12=0

I usually could do this yet i have completely forgotten what i need to do seeing as there is a number infront of the x^2

This equation is of the general form
a x^2 + bx + c = 0
The solution is always
x = [-b +/- sqrt (b^2 - 4ac)]/(2a)
= [1 +/- sqrt (1 + 288)]/12
= [1 +/- 17)/12
= 3/2 or -4/3

The equation could also have been factored into
(2x - 3)(3x + 4) = 0

14.
a)Write the prime factorization of 3600 using exponets

b)write the prime factorization of the square root of 3600

98

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