algebra , help
posted by jas20 .
Can someone help me set up the equations thanks.
Directions: Solve each of the following applications. Give all answers to the nearest thousandth.
Problem: Geometry. The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?
Let x = width of rectangle
Let x + 1 = length of rectangle
Remember that a^2 + b^2 = c^2
Therefore:
x^2 + (x + 1)^2 = 4^2
Can you take it from here to solve for x?
Don't forget to include the length and the width in your answer.

The length of a rectangle is 2 more than 3 times the width , if the perimeter is 100 meters what is the width of the rectangle
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