Integral
posted by drwls .
That's the same as the integral of sin^2 x dx.
Use integration by parts.
Let sin x = u and sin x dx = dv
v = cos x
du = cos x dx
The integral is u v  integral of v du
= sinx cosx + integral of cos^2 dx
which can be rewritten
integral of sin^2 x = sinx cos x + integral of (1  sin^2) dx
2 * (integral of sin^2 x dx)
=  sin x cos x + integral of dx
integral of sin^2 dx = (1/2) sin x cos x + x/2
integral of (1cos^2 x) dx
might be easy but i need to make sure
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