# Exponents-word problem

posted by
**Jen**
.

A culture starts at 8600 bacteria. After one hour the count is 10,000.

Find a function that models the number of bacteria n(t) after t hours.

The answer is n(t) = 8600e^.1506t

Where does this 0.1506 come from?

Thanks.

n(t) = 8600 e^(kt), where k is an unknown constant and t is the number of hours. We know that n(1), or the population after one hour is 10000. So 10000 = 8600e^(k*1)

10000/8600 = e^k

natural log ln(10000/8600) = k = .1508

The general expression is n(t) = no* e^(t/T), where T is the time for an increase by a factor of e.

In this case,

10000 = 8600 e^(1/T)

That equation can be solved for T.

10000/8600 = 1.16279 = e^(1/T)

Take the natural log of both sides.

0.15082 = 1/T

n(t) = e^(0.15082 t)

The 0.1506 in your version is not quite right.