A bowling ball (mass=72kg,Radius=0.11m) and A billiard ball (mass=0.47kg, Radius=0.028m)May each be treated as uniform sheres. What is the magnitude of the maximum gravitational force that each can exert on the other .
The maximum gravitational force occurs when they are in contact, i.e., as close together as possible. At that separation, the distance between the centers is
R = r1 + r2 = 0.128 m.
The maximum attractive force is
F = G* M1 * M2/R^2
where G is the universal constant of gravity. Look up G and compute that number.
The universal constant of gravity, denoted as G, is approximately 6.67430 × 10^-11 N(m/kg)^2.
To calculate the magnitude of the maximum gravitational force between the two spheres, we need to determine the masses of the bowling ball (M1) and the billiard ball (M2).
Given:
- Mass of the bowling ball, M1 = 72 kg
- Mass of the billiard ball, M2 = 0.47 kg
- Distance between the centers of the spheres, R = 0.128 m
Now we can substitute these values into the equation:
F = G * M1 * M2 / R^2
Calculating the denominator:
R^2 = (0.128 m)^2 = 0.016384 m^2
Now let's substitute the values:
F = (6.67430 × 10^-11 N(m/kg)^2) * (72 kg) * (0.47 kg) / 0.016384 m^2
Calculating this expression will give us the magnitude of the maximum gravitational force that each sphere can exert on the other.