I couldn't find the sets of factors that add up to -13 in this problem. Plz help, anything is greatly appreciated!
x^2-13x+36
Thx for helping ppl!
you could use the quad. eqn which is -b plus or munus sq root of b squared minus 4 ac all over 2 a
That is a good idea but I need to solve it by factoring, which uses a different method of solving it. Thx for helping out though, rach!
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did i do the ^ rose right? LOL
To find the sets of factors that add up to -13 in the given quadratic equation x^2 - 13x + 36, we can use factoring.
Step 1: Write down the equation: x^2 - 13x + 36
Step 2: Look for two numbers that multiply to give you the constant term (36) and add up to give you the coefficient of the middle term (-13). In this case, the numbers are -4 and -9.
Step 3: Rewrite the middle term (-13x) as the sum of these two numbers (-4x - 9x): x^2 - 4x - 9x + 36.
Step 4: Group the terms into pairs and factor by grouping:
(x^2 - 4x) - (9x - 36)
x(x - 4) - 9(x - 4)
Step 5: Notice that both terms have a common factor of (x - 4), so we can factor that out:
(x - 4)(x - 9)
Therefore, the factored form of the quadratic equation x^2 - 13x + 36 is (x - 4)(x - 9).
Now we can see that the two factors are (x - 4) and (x - 9), which will give us the sets of factors that add up to -13. In this case, the factors are -4 and -9.
So, the sets of factors that add up to -13 are (-4, -9).
I hope this explanation helps! Let me know if you have any further questions.