Math/Physics

posted by .

The velocity v of a particle moving in the xy plane is given by v = (6.0t - 4.0t2) i + 4.0 j, with v in meters per second and t (> 0) is in seconds.

What is the acceleration when t = 3.0 seconds? When is the acceleration zero? When is the velocity zero? When does the speed equal 10 m/s?

Please help :)

a= d^2/dt^2= you do it.

For the acceleration, calculate dv/dt.
dv/dt = (6.0 - 8.0 t) i
Plug in t=3 for the acceleration at that time. Set dv/dt = 0 and solve for t when acceleration = 0.
Speed is sqrt [(6t-4t^2)^2 +4^2]
Set it equal to 10 and solve for t, to do the last part of your questiuon.

so: 10=sqrt[(6t-4t^2)^2 + 4^2], so then I square both sides and get 100=[(6t-4t^2)^2 + 4^2]. Then what do I do, I'm stuck...

When is speed equal to 10m/s.

10=sqrt[(6t-4t^2)^2 +4^2]
100=[(6t-4t^2)^2 + 4^2].
subtract 4^2 from each side.
Take the square root of each side.
solve for t.

  • Math/Physics -

    so when is the velocity zero then?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physics

    A particle starts from the origin with velocity 2i m/s at t = 0 and moves in the xy plane with a varying acceleration given by 2 (sq root t) where is in meters per second squared and t is in seconds. (a) Determine the velocity of the …
  2. Calculus (Derivatives)

    Two particles are moving in straight lines. The displacement (in meters) of particle 1 is given by the function e^(4cos(t)) , where t is in seconds. The displacement (in meters) of particle 2 is given by the function -(t^3)/(3) - (t^2)/(2) …
  3. physics

    The acceleration of a particle moving only on a horizontal plane is given by a= 3ti +4tj, where a is in meters per second-squared and t is in seconds. At t = 0s, the position vector r= (20.0 m)i + (40.0 m)j locates the particle, which …
  4. physics

    The acceleration of a particle moving only on a horizontal plane is given by a= 3ti +4tj, where a is in meters per second-squared and t is in seconds. At t = 0s, the position vector r= (20.0 m)i + (40.0 m)j locates the particle, which …
  5. Physics

    A particle moved along the x axis with a constant acceleration of -85.0 meters per second squared. The initial position of the particle was at the origin and its initial velocity was +325 meters per second. Find the position of the …
  6. physics

    The position vector r of a particle moving in the xy plane is r=2ti+2sin[(pi/4)t]j , with is in meters and t in seconds. (a) Calculate the x and y components of the particle's position at , and 4.0 s and sketch the particle's path …
  7. Physics

    The acceleration of a particle moving only on a horizontal xy plane is given by , where is in meters per second-squared and t is in seconds. At t = 0, the position vector locates the paticle, which then has the velocity vector . At …
  8. Physics

    The acceleration of a particle moving only on a horizontal xy plane is given by a=5ti+6tj, where a is in meters per second-squared and t is in seconds. At t=0, the position vector r=(19.0m)i+(39.0m)j locates the particle, which then …
  9. Physics

    The acceleration of a particle moving only on a horizontal xy plane is given by a=5ti+6tj, where a is in meters per second-squared and t is in seconds. At t=0, the position vector r=(19.0m)i+(39.0m)j locates the particle, which then …
  10. Calculus(math)

    A particle is moving on a straight line in such a way that its velocity v is given by v(t)=2t+1 for 0≤t≤5 where t is measured in seconds and v in meters per second. What is the total distance traveled (in meters) by the …

More Similar Questions