quad. eq.
posted by chrisw
find 3 consecutive integers such that the product of the second and third integer is 20
Take three integers x, y, and z.
The for xyz, we want y*z = 20
The factors of 20 are
20*1
10*2
5*4.
20*1 are not consecutive.
10*2 are not consecutive.
But 5 and 4 are consecutive; therefore, we just add 3 in front to make it 345.
These are three consecutive integers and the second and third multiply to give 20.
n, n+1, n+2 are the integers.
(n+1)(n+2)=20
solve for n.
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