# Permutations

posted by
**Kevin**
.

I am having trouble with this maths problem:

There are 8 people at a round table - 6 guests, 2 hosts. How many possible arrangements are there if the 2 hosts aren't allowed to sit next to each other.

Thanks

hint:

sit the two host first, then let the guest find their seats. So, there are 8 choices for the 1st host, 5 remaining choices for the 2nd host, 6 remaining choices for the 1st guest, 5 for the 2nd guest, and so on.

Take it from here.