Permutations
posted by Kevin .
I am having trouble with this maths problem:
There are 8 people at a round table  6 guests, 2 hosts. How many possible arrangements are there if the 2 hosts aren't allowed to sit next to each other.
Thanks
hint:
sit the two host first, then let the guest find their seats. So, there are 8 choices for the 1st host, 5 remaining choices for the 2nd host, 6 remaining choices for the 1st guest, 5 for the 2nd guest, and so on.
Take it from here.
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