At a depth of 10.9 km, the Challlenger deep in the Marianas Trench of the Pacific Ocean is the deepest site in any ocean. In 1960, Donald Walsh and Jacques Piccard reached the challenger deep in the bathy scaph trieste. Assuming that sea water has a uniform density of 1024km/m^(3), approximate hydrostatic pressure (in atmospheres) that the trieste had to withstand.
What is the weight of a column of water of area A of height 10.9 km.
Average height is half that, the mass is density*volume.
Pressure = weight/area
That is the external pressure on the boat due to water. Now, one has to know the internal air pressure to get net pressure, and don't forget to include atmospheric pressure at the surface: it is pressing down on the water.
hello?
can you explain this alittle more thank you :)
To get the pressure at that depth, figure the weight of a column of water above it of Area A, height h. Add the atmopheric pressure at the top. That will give you absolute pressure (weight/area) on the sub. To get the net pressure on the walls, subtract the inside pressure, which was not given.
Certainly! In order to determine the hydrostatic pressure that the Trieste had to withstand at a depth of 10.9 km in the Challenger Deep, we need to calculate the weight of a column of water above that depth.
First, we need to find the weight of the column of water. The weight of an object is given by the equation: weight = mass * gravity. In this case, the mass is equal to the density of the water (1024 kg/m^3) multiplied by the volume of water. The volume can be calculated by multiplying the area (A) of the column of water by the height (h) of the column, which is 10.9 km in this case.
So, weight = density * volume = density * (A * h).
To find the pressure, we then divide the weight by the area (A) of the column of water: pressure = weight / A.
Now, it's important to note that this will give us the external pressure on the Trieste due to the water. To get the net pressure on the walls of the Trieste, we need to subtract the inside pressure of the submersible. Unfortunately, the question doesn't provide that information. Additionally, we need to consider the atmospheric pressure at the surface, as it is also pressing down on the water.
To get the absolute pressure on the Trieste, we add the atmospheric pressure at the surface to the pressure calculated earlier: absolute pressure = pressure + atmospheric pressure.
In summary, to approximate the hydrostatic pressure that the Trieste had to withstand at a depth of 10.9 km in the Challenger Deep, we need to calculate the weight of a column of water above that depth using the equation weight = density * (A * h). Then, we can find the pressure by dividing the weight by the area of the column (pressure = weight / A). Finally, to get the absolute pressure on the Trieste, we add the atmospheric pressure at the surface to the calculated pressure.