Thank you I did figure it out i think:
so the problem was
((w)-(1)/(4))^2
The final answer that i got was
w^2-(1)/(2)w+ (1)/(16)
Sorry, no again. :) Make sure you really look at how to multiply binomials and FOIL them out. It will come back to haunt you. a lot.
These are the steps i did:
(w-(1)/(4))^2
so from the problem i did this:
(w-(1)/(4))(w-(1)/(4))
so then i foil out:
=w^2-(1)/(4)w-(1)/(4)w+(1)/(16)
then i combined like terms
to get my answer
w^2-(1)/(2)w+(1)/(16)
You have the answer right, but don't do it like that. Do the numerator and denominator separately to make your life a little easier.
Yes, you have the correct final answer. However, let me explain a better way to expand the expression and simplify it step-by-step.
To expand ((w) - (1)/(4))^2, you can use the binomial theorem or simply multiply the binomial by itself. Let's go through it step-by-step:
Step 1: Apply the distributive property to the two terms inside the parentheses:
(w - (1)/(4)) * (w - (1)/(4))
Step 2: Use the FOIL method to multiply the terms:
(w * w) + (w * (-1)/(4)) + ((-1)/(4) * w) + ((-1)/(4) * (-1)/(4))
Step 3: Simplify each multiplication:
w^2 - (1)/(4)w - (1)/(4)w + (1)/(16)
Step 4: Combine like terms:
w^2 - (1)/(2)w + (1)/(16)
So, the final answer is indeed w^2 - (1)/(2)w + (1)/(16).
Remember to always double-check your calculations and simplify fractions whenever possible.