math,correction
posted by Jasmine20 .
Directions:Multiply
Problem:
((x)/(3)+(3)/(4)) ((3x)/(4)(3)/(5))
so the answer for it i got:
((20x^2+20x36)/(80))
I worked it and I have what you have EXCEPT 29x instead of 20x. If you can't find the error, post your work and we can help you find it.
PLEASE HELP ME FIND MY ERROR....THIS IS WHAT I DID.
Directions:Multiply
Problem:
((x)/(3)+(3)/(4)) ((3x)/(4)(3)/(5))
The steps i took:
First i simplify between (x)/(3) and (3)/(4) the common denominator is 12.
Then multiplied: x(4) and 3(3)= ((4x+9)/(12))
between (3x)/(4) and (3)/(5) the common denominator is 20.
so then i multiplied: 3x(5) and 3(4)=
(15x12)/(20)
Now i have:((4x+9)/(12))((15x12)/(20))
NOw i multiplied: ((4x+9)(15x)/(240))
now i factored out a 3 out of the top to get:
3((4x+9)(5x4)/(240))
now i simplify again:
((4x+9)(5x4)/80)
now foil the top:
f=4x(5x)
o=4x(4)
i=9(5x)
l=9(4)
(4x+9)(5x4)
=4x(5x)+4x(4)+9(5x)+9(4)
=20x^216x+45x36
=20x^2+20x36
NOW i just put that back in:
((4x+9)(5x4)/(80))
so that's how i came up with:
((20x^2+20x36)/(80))
((x)/(3)+(3)/(4)) ((3x)/(4)(3)/(5))
The steps i took:
First i simplify between (x)/(3) and (3)/(4) the common denominator is 12.
Then multiplied: x(4) and 3(3)= ((4x+9)/(12))
between (3x)/(4) and (3)/(5) the common denominator is 20.
so then i multiplied: 3x(5) and 3(4)=
(15x12)/(20)
Now i have:((4x+9)/(12))((15x12)/(20))ok to here.
NOw i multiplied: ((4x+9)(15x12)/(240))
you dropped the 12
now i factored out a 3 out of the top to get:
3((4x+9)(5x4)/(240))
now i simplify again:
((4x+9)(5x4)/80)
now foil the top:
f=4x(5x)
o=4x(4)
i=9(5x)
l=9(4)
(4x+9)(5x4)
=4x(5x)+4x(4)+9(5x)+9(4)
=20x^216x+45x36
=20x^2+20x36
OKAY I DON'T SEE IT CAN YOU EXPLAIN TO ME WHAT AM I SUPPOST TO DO.OR WHAT SHOULD IT LOOK LIKE
NOw i multiplied: ((4x+9)(15x12)/(240))
you dropped the 12.
(4x+9)(15x12)/240 =
FOIL it.
(60x^2 48x +135x 108)/240 =
Combine terms.
(60x^2 + 87x 108)/240 =
Divide by 3.
(20x^2 + 29x 36)/80 =
I don't know how your are to leave it in final form but I'm sure you can take it from here.
now i factored out a 3 out of the top to get:
3((4x+9)(5x4)/(240))
now i simplify again:
((4x+9)(5x4)/80)
now foil the top:
f=4x(5x)
o=4x(4)
i=9(5x)
l=9(4)
(4x+9)(5x4)
=4x(5x)+4x(4)+9(5x)+9(4)
=20x^216x+45x36
=20x^2+20x36
I appreciate all your help....especially correcting my wrongness.
Respond to this Question
Similar Questions

math,factoring,help
Can someone please show me step by step how to do these. I've read the book and there examples and It is just not clicking. Directions: Factor each of the following polynomials completely Problem:#1 14x^220x+6 Directions:Find all … 
someone help
my post is still on this page as algebra, could someone elaborate on what bobpursley tried to help me with. See your original post. I am guessing you are referring to your question 5)Simplify:(5x4)^2 and your answer= 25x^2  16 (5x4)^2 … 
Math
solve the equation 20x^3 +44x^2 17x 5 given that 5/2 is a zero of f(x) 20x^3 +44x^2 17x 5 I used synthetic division and got 20x^26x2=0 took 2 and divided it out of that equation 2(x+5/2)=10x^2 3x1 then i factored it out the … 
math
5(3+4x)6>=129 I get 2 different answers on this one. 15+20x6>=129 15+20x6+6>=129+6 15+20x>=135 1515+20x>=13515 20x>=120 20x/20>=120/20 x>=6 Is this worked out properly, are there any shortcuts? 
AlgebraPlease check
5  sqrt of 20x + 4 >= 3 5 20x + 4 >= 3 54  20x >= 3 1  20x >= 31 20x >= 4 x<= 15 Possible answers are x<=3 1/5 <= x<= 3 x >= 1/5 x >= 0 I think it is 1/5<=x<=3 because both solutions … 
Microbiology
You need 3.5L of 50mM NaCl from your 20X stock. How would you accomplish this: 20X stock __________ml Pure Water ___________ml From whatever number I plugged in trying to solve it, I got: 175ml of 20X stock and 3,430ml of Pure Water. … 
Math
Find the intersection of two lines. i have the answer just please tell me how it was made 4x3y4=0 , 4x+2y+5=0 5y/5 = 9/5 y= 9/5 4x3(9/5)4=0 5(4x+27/54=0) 20x+2720=0 20x+7=0 20x/20=7/20 x=7/20 (7/20, 9/5 
math
Find the product. (2x)(10x) A.20x B.12x C.20x^2 D.5x Is the answer A? 
Trig
Find the derivative using the product rule. {sqrt(x+8)}*(x^2+20x) (x+8)^1/2(2x+20) minus (1/2)(x+8)^1/2(x^2+20x) I'm not feeling confident I am on the right track and I have a quiz tomorrow over this. 
Trig
Find the derivative. {sqrt(x+8)}*(x^2+20x) (x+8)^1/2(2x+20) minus (1/2)(x+8)^1/2(x^2+20x) I'm not feeling confident I am on the right track and I have a quiz tomorrow over this.