factoring cubes
posted by Linds .
how to factor x^327
well since 27 is a perfect cube and so is x^3 wouldn't the answer be x3?
no, its something like (2x3)(?x^2+?X+?) i don't know how to figure all the parts out.
Here's the format for the difference between two cubes:
(a  b)(a^2 + ba + b^2) = a^3  b^3.
Using this format for your problem:
a = x, b = 3 (the cubed root of 27 is 3).
(x  3)(x^2 + 3x + 9) = x^3  27
I hope this will help.
yes thank you so much!
oooooo yeah now i remember.
since it is minus the formula should be something like:
(ab)(a^2 + ab + b^2)
x^327
(x3)(x^2 +3x+ 9)
^^i think that's the answer
how about 8x^327? how do you do that?
a=2x
b=3
You can use the same format because the cubed root of 8x^3 is 2x.
Here's the format again for the difference between two cubes:
(a  b)(a^2 + ba + b^2) = a^3  b^3.
Using the format:
a = 2x, b = 3 (the cubed root of 27 is 3).
(2x  3)(4x^2 + 6x + 9) = 8x^3  27
And there you have it!
Hi Math Guru is there a way to figure out
(a  b)(a^2 + ba + b^2) = a^3  b^3
without just memorizing the formula?

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