Calculus
posted by Linds .
find derivitive of 1/square root of x
1/square root of x = x^(1/2)
The derivative is 1/2 x^(3/2)
can you keep going on the problem to not have negative exponents?
You can also use that the derivative of
1/f(x) is given by:
f'(x)/[f(x)]^2
If you take f(x) = sqrt(x) and use that f'(x) = 1/[2*sqrt(x)], you find that the derivative is given by:
1/2 * 1/[sqrt(x)]^3
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