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algebra

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Divide (3x^3-x^2+8x-9) by (x-1)
Please help!

I'll show you how this works out:

3x^2 + 2x + 10
x - 1 | 3x^3 - x^2 + 8x - 9
3x^3 - 3x^2
2x^2 + 8x
2x^2 - 2x
10x - 9
10x - 10
1

Remember when you subtract, you change the signs. This did not divide evenly, so you will have a remainder of 1.

I hope this helps.

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