# pre-calculus

posted by
**emma**
.

What is the base of the function F(x) = b to the power of x if the graph has points of (1/3, 2)and another off the subject one if g(x)= log 7 x what is g(1/49)?

If F(x) = 2 when x = 1/3, and if the fucntio is of the form

F(x) = b^x, then

2 = b^(1/3)

Cube both sides of the equation.

b = 8

If g(x) = log (7x), then

g(1/49) = log (1/7) = -log 7