precalculus
posted by emma .
What is the base of the function F(x) = b to the power of x if the graph has points of (1/3, 2)and another off the subject one if g(x)= log 7 x what is g(1/49)?
If F(x) = 2 when x = 1/3, and if the fucntio is of the form
F(x) = b^x, then
2 = b^(1/3)
Cube both sides of the equation.
b = 8
If g(x) = log (7x), then
g(1/49) = log (1/7) = log 7
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