Algebra II factoring
posted by Lane .
I need help. i am having trouble factoring trinomials into binomials.
an example problem is 4n^25n6
can someone show me step by step how to factor these kind of problems easily?
Take the coefficient of your quadratic term in this case 4 and multiply it by your constant term in this case 6. You get 24. Then you want to figure out two numbers which when multiplied together give you 24 and when added together give you the value of the coefficient of your linear term in this case 5.
So, the two numbers are 8 and 3.
Take those two numbers and rewrite your problem changing you linear term in this case 5n using 8 and 3.
Changed problem is: 4n^28n+3n6
Now factor by grouping. The first two terms can be factored into 4n(n2) and the last two terms can be factored into 3(n2). Notice you have the same factor in parentheses.
So, the original problem (4n^25n6)can be factored into (4n+3)(n2).
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