calculus help lttle question
posted by david .
find the area of the regin bounded by the graphs of y=x^2=2x=3 and y=3.
i don't need help solving the problem and but i am a little confused.
ok the graph is a parabola and i drew a parobla with y= 3. now when find the area, am I finding the area on the top, above y=3 or on the bottom, below y=3.
i hope my question makes sense. basically, whick part of the graph am I finding the area of. top or bottom?
sorry about the equation. it is actually y=x^2+2x+3
find the area from the top of the parabola down to y=3
above ("top" of) y=3
y=3 cuts the parabola at (2,3)and (0,3), so the area bounded is the area of the parabola below the line y=3.
its area is integral(3  x^2  2x  3)dx from 2 to 0
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