math check again please
posted by jasmine20 .
I have a slope of -3/4 and the y-intercept at 8
the equation looks like:
y= -3/4x + 8
can someone tell me if i'm correct when i'm graphing it.
the two points that cross in the x axis and y are
(0,8) and (10.5,0) am i correct?
correct on the formula. correct on the intercepts.
what about if i have this one:
y = -2x + 4
then would my graph coordinates where it crosses be:
(0,4) and (2,0)
and then this one:
equation: y = 5x -2
then it will be: (-2,0) and i don't know what will the other be?
right on the first.
On the second
y = 5x -2
if x=0, then y=-2 so (0,-2)
and if y=0, then
0=5x-2 or x=2/5 so (2/5 , 0)
so then it would be(0,-2) and it will actally be (.4,0)
yes, although the word "actually' implies that 2/5 is not correct but it is. 2/5 if you wish to use fractions and 0.4 if you wish to use decimal equivalents.
okay thank you for helping me relieve my unsureness.
find the slope
i have no idea how to do this
the point of intersection is -2?
im learning this!! does anyone know the answeer to y=6/5x-2 (do a t-chart) i don't know wat to do!