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math check again please

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I have a slope of -3/4 and the y-intercept at 8
the equation looks like:
y= -3/4x + 8

can someone tell me if i'm correct when i'm graphing it.

the two points that cross in the x axis and y are

(0,8) and (10.5,0) am i correct?

correct on the formula. correct on the intercepts.

what about if i have this one:
y = -2x + 4

then would my graph coordinates where it crosses be:

(0,4) and (2,0)

and then this one:

equation: y = 5x -2

then it will be: (-2,0) and i don't know what will the other be?

right on the first.

On the second

y = 5x -2
if x=0, then y=-2 so (0,-2)

and if y=0, then
0=5x-2 or x=2/5 so (2/5 , 0)

so then it would be(0,-2) and it will actally be (.4,0)

yes, although the word "actually' implies that 2/5 is not correct but it is. 2/5 if you wish to use fractions and 0.4 if you wish to use decimal equivalents.

okay thank you for helping me relieve my unsureness.

  • math check again please -

    find the slope


    i have no idea how to do this

  • math check again please -


  • math check again please -

    the point of intersection is -2?

  • math check again please -

    im learning this!! does anyone know the answeer to y=6/5x-2 (do a t-chart) i don't know wat to do!

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