A 55 kg boy and 40 kg girl usa a rope while engaged in a tug-of-war. If the girl accelerates towards the boy at 5.1 m/s/s, what is the acceleration of the boy towards the girl?
The force on the rope is the same both ways.
Forceonrope=massgirl*accelerationgirl
solve for the force, then
force=massboy*accelerationboy.
To find the acceleration of the boy towards the girl, we can set up the equation based on the given information.
We know that the force on the rope is the same for both the boy and the girl. Therefore, we can equate the forces on the rope:
Force on the rope = mass of the girl * acceleration of the girl
Let's substitute the given values into the equation:
Force on the rope = 40 kg * 5.1 m/s^2
Now, we can equate the force on the rope to the force on the boy:
Force on the rope = mass of the boy * acceleration of the boy
We can now solve for the acceleration of the boy:
mass of the boy * acceleration of the boy = 40 kg * 5.1 m/s^2
Dividing both sides by the mass of the boy, which is 55 kg, we get:
acceleration of the boy = (40 kg * 5.1 m/s^2) / 55 kg
Now we can calculate the result:
acceleration of the boy = 3.72 m/s^2
So, the acceleration of the boy towards the girl is 3.72 m/s^2.