posted by DANIELLE
When the digits of two-digits numbers are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number.
Can some one please help me here?
The tens digit is T, the units digit is U.
The number is TU, its value is 10T +U
Reverse it, subtract the origial number
10U + T - 10T -U =9
Those are the guiding equations. Simplify the first, and solve.
T=5 u=6 5 + 6=11