RATE, DISTANCE, TIME
posted by CINDY .
TIM PADDLED HIS KAYAK 12 KM UPSTREAM AGAINST A 3 KM/H CURRENT AND BACK AGAIN IN 5 HR 20 MINUTES. iN THAT TIME
HOW FAR COULD HE HAVE PADDLED IN STILL WATER
12/(v+3) + 12/(v3) = 5.33 hours
Solve for this speed in still water, v.
12(v3) + 12(v+3) = 5.33 (v^2 9)
24 v = 5.33 v^2  48
Use the quadratic equation and take the positive root for v.
v = 6.0 km/h
In the same time, the distance he could travel in still water is
D = 5.33 * v = 32 km

RATE, DISTANCE, TIME 
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