Business Calculus
posted by drwls .
The indefinite integral, or which call the "antiderivative", of f'(x)=6x8x^3
is f(x) = 3x^2  2x^4 + C
where C is any constant.
Plug in x = 2 to that to see what C is.
3 = 3*4  2*16 + C
Determine the antiderivative of the following function given the initial condition: f'(x)=6x8x^3 given that
f(2)=3
f'(x)=6x8x^3
f(x)= 6x^2/2  8x^4/4 + C
Put in x=2 and solve for C
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