Math
posted by Jamie .
For two consecutive integers, the sum of the smaller and twice the larger is 38. What are the integers?
Plz explain. Thanks
2(a+b)=38
Therefore:
a+b+(2(a+b)=38
a+b+2a+2b=38
3a+3b=38
3(a+b)=38
I got as far a here. I don't know if this helps. My last stop may be worng. This might help?
r u kidding me?this is like the easiest math ever..38 divide by 2 is 19 so a+b equals 19..
r u kidding me?this is like the easiest math ever..38 divide by 2 is 19 so a+b equals 19..
r u kidding me?this is like the easiest math ever..38 divide by 2 is 19 so a+b equals 19..
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