Math, rational inequalities
posted by agirl .
Please can someone help me solve this problem?
2/x + 6/x1 less than or = 5
8/x 1 <= 5 Now add 1 to each side
8/x <= 4 so x must be < 0
Multiply both sides by x (a negative number). This means you have to change the direction of the >
8 >= 4x
Divide both sides by 4
2 >= x
Multiply both sides by 1
2 <= x < 0
thanks so much but can you please post the solution in integral notation for me
2 6
___ + ____ < or =  5
X X  1
I'm also not sure how you got 8x1 I didn't know I could just add the two numerators if the denominators were different
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