Differentiation
posted by Jill .
How do you find f'(x), f''(x) of f(x) =ln (1x)
IF f(x) = ln (1x)
Then use the chain rule with u(x) = 1x
f(u) = ln u
df/dx = df/du du/dx
f'(x) = 1/(1x)
Use the chain rule again:
f"(x) = [1/(1x)^2]*(1) = 1/(1x)^2
What is the pattern there how can you give an expression for f ^(n) (x) [the nth derivative of f(x)]?
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