algebra
posted by sheila .
this is what u do on your first problem....first u take out the greatest common factor that would go into all of them...
4n^220n+24...now what number will go into all of them...well 4 will...4 will go into 4,20,and 24...so.
it would be like this..4(n^25n+6)...then theirs one more step...4(n2)(n3)
4x^222x+10 would be...2(2x^211x+5)...then u factor again...2(2x1)(x5)
1/2x^21/2would be 1/2(x^21)...then u factor again...1/2(x+1)(x1)
Factor:
4n²20n+24
4x²22x+10
1/2x²1/2
Thanks in advance.
On each, take out the common factor
2(2n²10n+12)
2(2x²11x+ 5)
1/2 (x²1)
Now you should be able to factor the inside.
Thanks, but that's where I get stuck. I thought like for the first one that you have to multipy two numbers together to get 12 and they have to add to 10. I can't think of 2 numbers, or am I just doing it wrong?
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