posted by Jen .
When I solve the inquality 2x^2 - 6 < 0,
I get x < + or - sqrt(3)
So how do I write the solution?
Is it (+sqrt(3),-sqrt(3)) or (-infinity, sqrt(3))?
So would this work?
abs x < ( sqrt 3 )
- sqrt 3<x<sqrt 3
The answer is given (+sqrt(3),-sqrt(3))
I don't know the reason