I'm not sure how to solve these problems.
Simplify
(3xsquare - 2x)divided by 15x - 10
Subtract
(2y/x-y) - 5x/4y
Solve
(27/x) = (8 - 5/x)
Simplify
(7m^7n^4/8m) divided by (9m^2n^9/5n^2)
1) 3x^2 - 2x/ 15x - 10
factorize both the numerator and denominator
x(3x-2)/ 5(3x-2)
= x/5 (the 3x-2 cancel each other
2) 2y(4y)-5x(x-y) / 4y(x-y)
The x-y cancel each other
8y^2 - 5x / 4y
4y goes in 8y^2 2 times
so the answer is
2y - 5x
3) NOT SURE ABT THAT
but i know that the 9m^2... part is gonna be multiplied to the 7m^7 part
CHECK UR WORKING OUT
To solve the equation (27/x) = (8 - 5/x), we can start by cross-multiplying:
27/x = (8 - 5/x)
27(x) = x(8 - 5/x)
Now distribute x on the right side:
27x = 8x - 5
Combine like terms by subtracting 8x from both sides:
27x - 8x = -5
Simplify the left side:
19x = -5
Divide both sides by 19 to isolate x:
x = -5/19
4) To simplify the expression (7m^7n^4/8m) divided by (9m^2n^9/5n^2), we can simplify both the numerator and denominator separately, and then divide:
Numerator simplification:
7m^7n^4 / 8m
Divide both the coefficients and subtract the exponents of m:
7/8 * m^7/m
Simplify:
7m^6 / 8
Denominator simplification:
9m^2n^9 / 5n^2
Divide both the coefficients and subtract the exponents of m and n:
9/5 * m^2/m^0 * n^9/n^2
Since any value raised to the power of 0 is 1, we have:
9/5 * m^2 * n^7
Now, divide the numerator by the denominator:
(7m^6 / 8) / (9/5 * m^2 * n^7)
To divide fractions, we multiply the first fraction by the reciprocal of the second fraction:
(7m^6 / 8) * (5/9 * 1/m^2 * 1/n^7)
Simplify the coefficients and combine the like terms with the same bases:
35m^6 / 72mn^7