# DRWLS CAN YOU ANSWER

posted by
**Jasmine202005**
.

How do i solve inequalitites with three variables. I still can't figure it outplease help.

x+y=1

y-z=-3

2x+3y+z=1

THE ANSWERS ARE3,-2,1 HOW DID THEY GET THAT ANSWER.

This can be solved a number of ways.

1) subsitition

2) determinants

3) matricies.

Substution:

x= 1-y

y= z+3 or x= 1-z-3

In the third equation , put those two things for x, and y.

2x+3y+z=1

then solve for z. Then go back and solve for x and y.

I've done that already such as

the book states the following

that the answer is -x-y=-1

how did they get there after adding equation 2 and three

Substitute x = 1-y and z = y+3 in the third equation. Then you get an equation in y only:

2(1-y) + 3y + (y+3) = 1

2y + 5 = 1

y = -2

Then use the equations for x and z again.

x = 1-(-2) = 3 etc.