DRWLS CAN YOU ANSWER
posted by Jasmine202005 .
How do i solve inequalitites with three variables. I still can't figure it outplease help.
x+y=1
yz=3
2x+3y+z=1
THE ANSWERS ARE3,2,1 HOW DID THEY GET THAT ANSWER.
This can be solved a number of ways.
1) subsitition
2) determinants
3) matricies.
Substution:
x= 1y
y= z+3 or x= 1z3
In the third equation , put those two things for x, and y.
2x+3y+z=1
then solve for z. Then go back and solve for x and y.
I've done that already such as
the book states the following
that the answer is xy=1
how did they get there after adding equation 2 and three
Substitute x = 1y and z = y+3 in the third equation. Then you get an equation in y only:
2(1y) + 3y + (y+3) = 1
2y + 5 = 1
y = 2
Then use the equations for x and z again.
x = 1(2) = 3 etc.
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